Question

select the equivalent expression.
\\(\frac{x^{-7}}{x^{-3} \cdot x}\\)
answer attempt 1 out of 3
\\(\frac{1}{x^5}\\) \\(x^5\\)
\\(\frac{1}{x^{11}}\\) \\(x^{11}\\)

Explanation:

Step1: Simplify denominator exponents

$x^{-3} \cdot x = x^{-3+1} = x^{-2}$

Step2: Divide using exponent subtraction

$\frac{x^{-7}}{x^{-2}} = x^{-7 - (-2)} = x^{-5}$

Step3: Rewrite negative exponent

$x^{-5} = \frac{1}{x^5}$

Answer:

$\frac{1}{x^5}$