Question

sept. 4 unit 1 #10 the student be able to calculate missing angles in a diagram
possible points: 10
find cj + ca + cb

Explanation:

Step1: Calculate distance between C and J

The coordinate of C is - 4 and J is - 1. The distance formula between two points \(x_1\) and \(x_2\) on a number - line is \(d=\vert x_2 - x_1\vert\). So \(CJ=\vert-1-(-4)\vert=\vert-1 + 4\vert = 3\).

Step2: Calculate distance between C and A

The coordinate of C is - 4 and A is 1. So \(CA=\vert1-(-4)\vert=\vert1 + 4\vert = 5\).

Step3: Calculate distance between C and B

The coordinate of C is - 4 and B is 4. So \(CB=\vert4-(-4)\vert=\vert4 + 4\vert = 8\).

Step4: Calculate the sum

\(CJ + CA+CB=3 + 5+8 = 16\).

Answer:

16