Question

show how to convert your experimental energy released per gram from kj/g to kcal/g. your calculation will start with the heat of combustion (slope) found in the section above. hide hint hint: 1 calorie = 1 kilocalorie = 1000 calories and 1 calorie = 4.18 joules 22.7kj/1g×1000 j/1 kj×1 cal/4.18 j×1 kcal/1000 cal =??kcal/g choices: reset 4.18 cal 1 j 1000 kj 1000 kcal 3. convert the experimental energy released to kcal/g the answer to this question depends on your answer to previous questions

Explanation:

Step1: Convert kJ to J

We know that $1\ kJ = 1000\ J$. So for $22.7\ kJ$, we multiply by the conversion factor $\frac{1000\ J}{1\ kJ}$.
$22.7\ \frac{kJ}{g}\times\frac{1000\ J}{1\ kJ}=22700\ \frac{J}{g}$

Step2: Convert J to cal

Since $1\ cal = 4.18\ J$, we multiply by the conversion factor $\frac{1\ cal}{4.18\ J}$.
$22700\ \frac{J}{g}\times\frac{1\ cal}{4.18\ J}\approx5430.62\ \frac{cal}{g}$

Step3: Convert cal to kcal

As $1\ kcal = 1000\ cal$, we multiply by the conversion factor $\frac{1\ kcal}{1000\ cal}$.
$5430.62\ \frac{cal}{g}\times\frac{1\ kcal}{1000\ cal}= 5.43062\ \frac{kcal}{g}\approx5.43\ \frac{kcal}{g}$

Answer:

$5.43\ \frac{kcal}{g}$