Question

show instructions question 2 of 20 | page 2 of 20 question 2 (1 point) a car accelerates at a rate of 3.0 m/s/s . if its original speed is 8.0 m/s, how many seconds will it take the car to reach a final speed of 26.0 m/s? a 8s b 7s c 5s d 6s

Explanation:

Step1: Recall the acceleration formula

The formula for acceleration is \( a=\frac{v_f - v_i}{t} \), where \( a \) is acceleration, \( v_f \) is final velocity, \( v_i \) is initial velocity, and \( t \) is time. We need to solve for \( t \), so rearranging the formula gives \( t=\frac{v_f - v_i}{a} \).

Step2: Identify the given values

We know that \( a = 3.0\space m/s^2 \), \( v_i=8.0\space m/s \), and \( v_f = 26.0\space m/s \).

Step3: Substitute the values into the formula

Substitute the values into \( t=\frac{v_f - v_i}{a} \): \( t=\frac{26.0 - 8.0}{3.0} \)

Step4: Calculate the numerator first

\( 26.0 - 8.0=18.0 \)

Step5: Divide to find the time

\( t=\frac{18.0}{3.0} = 6\space s \)

Answer:

d. 6s