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questions 1 - 8 of 8 | page
| hw #4
questions of geometry
question 1 (1 point)
∠1 and ∠2 are complementary angles and ∠2 and ∠3 are supplementary angles. given the measure of ∠1, determine the m∠2 and m∠3.
m∠1 = 43°
m∠2 =
m∠3 =
blank 1:
blank 2:
question 2 (1 point)
using the following diagram, find m∠abc and m∠cbd.
Step1: Recall complementary - angle property
Complementary angles sum to 90°. Given $\angle1 = 43^{\circ}$ and $\angle1$ and $\angle2$ are complementary. So, $m\angle2=90^{\circ}-m\angle1$.
$m\angle2 = 90 - 43=47^{\circ}$
Step2: Recall supplementary - angle property
Supplementary angles sum to 180°. Given $\angle2$ and $\angle3$ are supplementary. So, $m\angle3 = 180^{\circ}-m\angle2$.
$m\angle3=180 - 47 = 133^{\circ}$
Since no diagram is provided for finding $m\angle ABC$ and $m\angle CBD$, we assume the above is for Question 1.
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$m\angle2 = 47^{\circ}$, $m\angle3 = 133^{\circ}$