Question

a side of the triangle below has been extended to form an exterior angle of 68°. find the value of x.

Explanation:

Step1: Recall exterior - angle property

The exterior angle of a triangle is equal to the sum of the two non - adjacent interior angles.

Step2: Set up the equation

We have the exterior angle \(68^{\circ}\), and the two non - adjacent interior angles are \(47^{\circ}\) and \(x\). So, \(x + 47^{\circ}=68^{\circ}\).

Step3: Solve for \(x\)

Subtract \(47^{\circ}\) from both sides of the equation: \(x=68^{\circ}- 47^{\circ}\).
\(x = 21^{\circ}\)

Answer:

\(21\)