Question

simple harmonic motion

when each spring has a spring
constant of 200 n/m, the spring
constant of the system is
200 n/m when the spring
constant of the second spring is
400 n/m, the spring constant of the
system is dropdown with 800 n/m, 600 n/m therefore,
when mul... connected to
a source ... spring constant of
the system is the dropdown of the
spring constants

Explanation:

Step1: Identify Spring Connection Type

The springs are connected in parallel (as seen from the diagram, they are side - by - side, pulling the same mass). For springs in parallel, the formula for the equivalent spring constant \(k_{eq}\) is \(k_{eq}=k_1 + k_2\).

Step2: Calculate Equivalent Spring Constant

We know that \(k_1 = 200\space N/m\) and \(k_2=400\space N/m\). Using the formula for parallel springs:
\(k_{eq}=k_1 + k_2=200 + 400=600\space N/m\)

Answer:

600 N/m