Question

simplify.
\frac{35v^{2}w^{4}}{28v^{5}w^{4}}

Explanation:

Step1: Simplify the coefficients

$\frac{35}{28} = \frac{5}{4}$

Step2: Simplify $v$ terms

$\frac{v^2}{v^5} = v^{2-5} = v^{-3} = \frac{1}{v^3}$

Step3: Simplify $w$ terms

$\frac{w^4}{w^4} = w^{4-4} = w^0 = 1$

Step4: Combine all simplified parts

$\frac{5}{4} \times \frac{1}{v^3} \times 1 = \frac{5}{4v^3}$

Answer:

$\frac{5}{4v^3}$