Question

simplify. assume x and y are greater than or equal to zero, and write your answer in simplest form.\\(\left(\sqrt{7x^{2}y}\
ight)^{2}\\)

Explanation:

Step1: Recall the property of square roots and exponents

For any non - negative real number \(a\), \((\sqrt{a})^{2}=a\). Here, \(a = 7x^{2}y\) and since \(x\geq0\) and \(y\geq0\), \(7x^{2}y\) is non - negative.

Step2: Apply the property

Using the property \((\sqrt{a})^{2}=a\), when \(a = 7x^{2}y\), we have \((\sqrt{7x^{2}y})^{2}=7x^{2}y\).

Answer:

\(7x^{2}y\)