Question

simplify. express your answer as a single term, without a denominator. $h^{0} \cdot h^{-7}$

Explanation:

Step1: Apply exponent product rule

When multiplying like bases, add exponents: $h^a \cdot h^b = h^{a+b}$
So $h^0 \cdot h^{-7} = h^{0 + (-7)}$

Step2: Simplify the exponent

Calculate the sum of exponents: $0 + (-7) = -7$
Result: $h^{-7}$

Answer:

$h^{-7}$