Question

simplify. express your answer using positive exponents. \\(\dfrac{3j^{-7}}{(3j)(j^{-3})}\\) submit

Explanation:

Step1: Simplify denominator first

Multiply terms in denominator:
$(3j)(j^{-3}) = 3j^{1 + (-3)} = 3j^{-2}$

Step2: Rewrite the original expression

Substitute simplified denominator:
$\frac{3j^{-7}}{3j^{-2}}$

Step3: Cancel constants and simplify exponents

Cancel 3, subtract exponents:
$\frac{j^{-7}}{j^{-2}} = j^{-7 - (-2)} = j^{-5}$

Step4: Convert to positive exponent

Use $a^{-n}=\frac{1}{a^n}$:
$j^{-5} = \frac{1}{j^5}$

Answer:

$\frac{1}{j^5}$