Question

simplify the expression using exponent rules. leave your answer in exponential form with a positive exponent. (1 point) \\(\frac{(9^3 \times 9)}{9^2} = \square\\)

Explanation:

Step1: Simplify the numerator using exponent rule \(a^m \times a^n = a^{m + n}\)

The numerator is \(9^3 \times 9\), and since \(9 = 9^1\), we have \(9^3 \times 9^1 = 9^{3 + 1}=9^4\)

Step2: Simplify the fraction using exponent rule \(\frac{a^m}{a^n}=a^{m - n}\)

Now the expression is \(\frac{9^4}{9^2}\), so we apply the rule: \(9^{4 - 2}=9^2\)

Answer:

\(9^2\) (or 81, but since we need exponential form with positive exponent, \(9^2\) is appropriate)