Question

simplify the following expression.
$(3x - 2)^2$
$?x^2 + \square x + \square$

Explanation:

Step1: Recall the formula for squaring a binomial

The formula \((a - b)^2 = a^2 - 2ab + b^2\). Here, \(a = 3x\) and \(b = 2\).

Step2: Apply the formula to \((3x - 2)^2\)

First, calculate \(a^2=(3x)^2 = 9x^2\). Then, calculate \(-2ab=-2\times(3x)\times2=-12x\). Finally, calculate \(b^2 = 2^2 = 4\). So, \((3x - 2)^2=9x^2-12x + 4\).

Answer:

The coefficient of \(x^2\) is \(9\), the coefficient of \(x\) is \(-12\), and the constant term is \(4\). So for the first box (coefficient of \(x^2\)) the answer is \(9\).