Question

simplify: \\(\frac{x^{5}y^{-4}}{x^{-3}y^{2}}\\)\
\\(\bigcirc\\) \\(\frac{y^{6}}{x^{8}}\\)\
\\(\bigcirc\\) \\(\frac{x^{8}}{y^{6}}\\)\
\\(\bigcirc\\) \\(x^{8}y^{6}\\)\
\\(\bigcirc\\) \\(\frac{y^{2}}{x^{2}}\\)\
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question 22\
1 pts\
simplify: \\(4x(9x - 7y)\\)\
\\(\bigcirc\\) \\(36x - 28xy\\)\
\\(\bigcirc\\) \\(36x^{2} - 28xy\\)\
\\(\bigcirc\\) \\(36x^{2} - 7y\\)\
\\(\bigcirc\\) \\(36x^{2} - 28y^{2}\\)

Explanation:

Step1: Apply exponent rule for $x$

$\frac{x^5}{x^{-3}} = x^{5 - (-3)} = x^{8}$

Step2: Apply exponent rule for $y$

$\frac{y^{-4}}{y^{2}} = y^{-4 - 2} = y^{-6} = \frac{1}{y^6}$

Step3: Combine the results

$x^{8} \cdot \frac{1}{y^6} = \frac{x^8}{y^6}$

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Step1: Distribute $4x$ to $9x$

$4x \cdot 9x = 36x^2$

Step2: Distribute $4x$ to $-7y$

$4x \cdot (-7y) = -28xy$

Step3: Combine the terms

$36x^2 - 28xy$

Answer:

1. $\frac{x^8}{y^6}$
2. $36x^2 - 28xy$