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8.3 simplify rational exponents (homework) score: 21.05/25 answered: 22/25 question 23 simplify. assume all variables are positive. (8y^(9/2))^(2/3)= question help: video written example submit question jump to answer
Step1: Apply power - of - a - product rule
Use the rule $(ab)^n=a^n\times b^n$. So, $(8y^{\frac{9}{2}})^{\frac{2}{3}} = 8^{\frac{2}{3}}\times(y^{\frac{9}{2}})^{\frac{2}{3}}$.
Step2: Simplify $8^{\frac{2}{3}}$
Rewrite $8$ as $2^3$. Then $8^{\frac{2}{3}}=(2^3)^{\frac{2}{3}}$. By the power - of - a - power rule $(a^m)^n=a^{mn}$, we have $(2^3)^{\frac{2}{3}}=2^{3\times\frac{2}{3}} = 2^2=4$.
Step3: Simplify $(y^{\frac{9}{2}})^{\frac{2}{3}}$
Using the power - of - a - power rule $(a^m)^n=a^{mn}$, we get $(y^{\frac{9}{2}})^{\frac{2}{3}}=y^{\frac{9}{2}\times\frac{2}{3}}=y^3$.
Step4: Combine the results
$8^{\frac{2}{3}}\times(y^{\frac{9}{2}})^{\frac{2}{3}}=4y^3$.
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$4y^3$