Question

simplify: $n^8 \div n^8$ *
$n^{16}$
undefined
$n^0 = 1$
0

Explanation:

Step1: Recall exponent rule for division

When dividing two exponents with the same base, we use the rule \( \frac{a^m}{a^n}=a^{m - n} \). Here, the base is \( n \), \( m = 8 \), and \( n = 8 \). So, \( n^{8}\div n^{8}=n^{8 - 8} \).

Step2: Simplify the exponent

Calculate \( 8 - 8 = 0 \), so we get \( n^{0} \).

Step3: Recall the zero - exponent rule

The zero - exponent rule states that for any non - zero number \( a \), \( a^{0}=1 \). Assuming \( n
eq0 \) (since if \( n = 0 \), \( 0^{8}\div0^{8} \) is undefined, but in the context of this problem, we use the zero - exponent rule), \( n^{0}=1 \).

Answer:

\( n^{0}=1 \) (the option corresponding to this result)