Question

sketch the graph of the following function: (x - 3)^2+(y + 2)^2 = 4 center of the circle: radius:

Explanation:

Step1: Recall circle - equation formula

The standard form of the equation of a circle is $(x - a)^2+(y - b)^2=r^2$, where $(a,b)$ is the center of the circle and $r$ is the radius.

Step2: Identify the center of the circle

For the equation $(x - 3)^2+(y + 2)^2 = 4$, comparing with the standard - form, we have $a = 3$ and $b=-2$. So the center of the circle is $(3,-2)$.

Step3: Identify the radius of the circle

Since $r^2 = 4$, then $r=\sqrt{4}=2$.

Answer:

Center: $(3,-2)$
Radius: $2$