Question

smithers thinks that a special juice will increase the productivity of workers. he creates two groups of 50 workers each and assigns each group the same task (in this case, theyre supposed to staple a set of papers). group a is given the special juice to drink while they work. group b is not given the special juice. after an hour, smithers counts how many stacks of papers each group has made. group a made 1,587 stacks, group b made 2,113 stacks. identify the: 1. control group: 2. independent variable: 3. dependent variable: 4. what should smithers conclusion be? 5. how could this experiment be improved?

Explanation:

1. The control group is the one not receiving the treatment (special juice), which is Group B.
2. The independent variable is what is being changed or manipulated, here it's the presence or absence of the special juice.
3. The dependent variable is what is being measured, which is the number of stacks of papers made.
4. Since Group B made more stacks than Group A, Smithers should conclude that the special juice did not increase productivity.
5. The experiment could be improved by increasing the sample - size, repeating the experiment multiple times, controlling for other factors like worker experience, and ensuring random assignment of workers to groups.

Answer:

1. Group B
2. The special juice (presence or absence)
3. The number of stacks of papers made
4. The special juice did not increase productivity.
5. Increase sample - size, repeat the experiment, control for other factors, ensure random assignment.