QUESTION IMAGE
Question
solve for (t).
(3(t + 10)-6 < - 15)
Step1: Expand the left - hand side
$3(f + 10)-6=3f+30 - 6=3f + 24$. So the inequality becomes $3f+24\lt - 15$.
Step2: Subtract 24 from both sides
$3f+24-24\lt - 15 - 24$, which simplifies to $3f\lt-39$.
Step3: Divide both sides by 3
$\frac{3f}{3}\lt\frac{-39}{3}$, so $f\lt - 13$.
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$f\lt - 13$