Question

solve for j.
2(j + 3) = 16
j =

1. solve for d.

3 = -\frac{1}{6}d + 1
write your answer as a fraction decimals.
d =

Explanation:

Solve for \( j \):

Step 1: Divide both sides by 2

To isolate the parentheses, divide both sides of the equation \( 2(j + 3) = 16 \) by 2.
\( \frac{2(j + 3)}{2} = \frac{16}{2} \)
Simplifying gives \( j + 3 = 8 \).

Step 2: Subtract 3 from both sides

To solve for \( j \), subtract 3 from both sides of the equation \( j + 3 = 8 \).
\( j + 3 - 3 = 8 - 3 \)
Simplifying gives \( j = 5 \).

Step 1: Subtract 1 from both sides

Start with the equation \( 3 = -\frac{1}{6}d + 1 \). Subtract 1 from both sides to isolate the term with \( d \).
\( 3 - 1 = -\frac{1}{6}d + 1 - 1 \)
Simplifying gives \( 2 = -\frac{1}{6}d \).

Step 2: Multiply both sides by -6

To solve for \( d \), multiply both sides of the equation \( 2 = -\frac{1}{6}d \) by -6.
\( 2 \times (-6) = -\frac{1}{6}d \times (-6) \)
Simplifying gives \( -12 = d \), or \( d = -12 \).

Answer:

\( j = 5 \)

Solve for \( d \):