QUESTION IMAGE
Question
solve for y. do not convert your answer to decimal form.
draw
(right triangle with hypotenuse 8, angle 60° at the base, base length y)
show your work here
hint: to add the square root symbol (√), type
oot\
Step1: Identify the trigonometric ratio
We have a right - triangle with hypotenuse \(c = 8\) and we want to find the adjacent side \(y\) to the \(60^{\circ}\) angle. The cosine of an angle in a right - triangle is defined as \(\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}\). So, \(\cos(60^{\circ})=\frac{y}{8}\).
Step2: Recall the value of \(\cos(60^{\circ})\)
We know that \(\cos(60^{\circ})=\frac{1}{2}\). Substituting this value into the equation \(\cos(60^{\circ})=\frac{y}{8}\), we get \(\frac{1}{2}=\frac{y}{8}\).
Step3: Solve for \(y\)
To solve for \(y\), we can cross - multiply. Cross - multiplying gives us \(y = 8\times\frac{1}{2}\).
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\(y = 4\)