Question

solve by elimination
$x + y = 3$
$x - 3y = -29$
$\bigcirc$ $(-1,5)$
$\bigcirc$ $(3,2)$
$\bigcirc$ $(-2,5)$
$\bigcirc$ $(-5,8)$
$\bigcirc$ $(-4,-1)$
$\bigcirc$ $(3,-1)$
$\bigcirc$ $(4,1)$
$\bigcirc$ $(1,-3)$
$\bigcirc$ $(-5,4)$
$\bigcirc$ $(0,-2)$
$\bigcirc$ no solution
$\bigcirc$ infinite solutions

Explanation:

Step1: Subtract equations to eliminate $x$

$(x + y) - (x - 3y) = 3 - (-29)$

Step2: Simplify to solve for $y$

$x + y - x + 3y = 32$
$4y = 32$
$y = \frac{32}{4} = 8$

Step3: Substitute $y=8$ into first equation

$x + 8 = 3$

Step4: Solve for $x$

$x = 3 - 8 = -5$

Answer:

(-5,8)