Question

solve for x.
$x^3 + 5x^2 + 6x = 0$
$x = -3, ?, \square$
enter the solutions in ascending order.

Explanation:

Step1: Factor out common x

$x(x^2 + 5x + 6) = 0$

Step2: Factor quadratic expression

$x(x+2)(x+3) = 0$

Step3: Set each factor to 0

$x=0$, $x+2=0$, $x+3=0$

Step4: Solve for x values

$x=0$, $x=-2$, $x=-3$

Step5: Sort values ascending

$-3 < -2 < 0$

Answer:

$x = -3, -2, 0$