Question

solve the equation below. what’s the value of c?
\\(\frac{4(6c + 4)}{8} = -2c + 4\\)
\\(\frac{6c + 4}{2} = -2c + 4\\)
\\(3c + 2 = -2c + 4\\)
multiply each side by 2c
subtract 2c from both sides
divide each side by 2c
add 2c to each side

Explanation:

Step1: Analyze the equation \(3c + 2=-2c + 4\)

We need to get all the \(c\) terms on one side. To do this, we can add \(2c\) to both sides to eliminate the \(-2c\) on the right.

Step2: Add \(2c\) to both sides

\(3c+2 + 2c=-2c + 4+ 2c\)
Simplify both sides: \(5c + 2=4\)

Step3: Subtract 2 from both sides

\(5c+2 - 2=4 - 2\)
Simplify: \(5c = 2\)

Step4: Divide by 5

\(c=\frac{2}{5}=0.4\)
But first, the step to get from \(3c + 2=-2c + 4\) to the next step is to add \(2c\) to each side.

Answer:

The correct operation is to add \(2c\) to each side, so the answer is "Add \(2c\) to each side". And the value of \(c\) is \(\frac{2}{5}\) (or \(0.4\)).