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solve the equation below. whats the value of v?subtract 6v from both si…

Question

solve the equation below. whats the value of v?subtract 6v from both sides of the equation to get rid of the 6v on the left, so that all the v terms are on the right side of the equation.$\frac{1}{2}(12v - 8) = 8v + 10$$6v - 4 = 8v + 10$$- 6v quad quad - 6v$$square = square$

Explanation:

Step1: Simplify left-hand side

$\frac{1}{2}(12v - 8) = 6v - 4$

Step2: Subtract $6v$ from both sides

$6v - 4 - 6v = 8v + 10 - 6v$

Step3: Simplify both sides

$-4 = 2v + 10$

Step4: Isolate the $v$-term

$2v = -4 - 10$
$2v = -14$

Step5: Solve for $v$

$v = \frac{-14}{2}$

Answer:

$v = -7$

(Note: The blanks from the subtraction step are: Left blank: $-4$, Right blank: $2v + 10$)