Question

solve the equation by the square root property.
3x² + 1 = 19
the solution set is {}.
(simplify your answer. type an exact answer, using radicals as needed. use a comma to

Explanation:

Step1: Isolate the $x^2$ term

Subtract 1 from both sides:
$3x^2 + 1 - 1 = 19 - 1$
$3x^2 = 18$

Step2: Solve for $x^2$

Divide both sides by 3:
$\frac{3x^2}{3} = \frac{18}{3}$
$x^2 = 6$

Step3: Apply square root property

Take square roots of both sides, accounting for positive and negative roots:
$x = \pm\sqrt{6}$

Answer:

$\sqrt{6}, -\sqrt{6}$