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Question
solve the exponential equation for x.
64^{7x - 8} = 1
x =
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solving exponential equations using
Step1: Recall the property of exponents
Any non - zero number raised to the power of 0 is 1, i.e., $a^0 = 1$ for $a
eq0$. In the equation $64^{7x - 8}=1$, we know that $64
eq0$, so we can set the exponent equal to 0.
Step2: Solve for x
Set $7x - 8 = 0$.
Add 8 to both sides of the equation: $7x=8$.
Divide both sides by 7: $x=\frac{8}{7}$.
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$\frac{8}{7}$