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solve the following system of linear equations by substitution and dete…

Question

solve the following system of linear equations by substitution and determine whether the system has one solution, no solution, or an infinite number of solutions. if the system has one solution, find the solution.
\

$$\begin{cases} 4x + y = 21 \\\\ 8x + 2y = 24 \\end{cases}$$

answer
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\bigcirc one solution \quad (\quad, \quad)
\bigcirc no solution
\bigcirc infinite number of solutions

Explanation:

Step1: Solve for y from first equation

From \(4x + y = 21\), we get \(y = 21 - 4x\).

Step2: Substitute y into second equation

Substitute \(y = 21 - 4x\) into \(8x + 2y = 24\):
\(8x + 2(21 - 4x) = 24\)

Step3: Simplify the equation

Expand: \(8x + 42 - 8x = 24\)
Simplify: \(42 = 24\), which is false.

Answer:

No Solution