Question

solve the inequality.
\\(\frac{1}{2}x + 3 \geq 5x + 2\\)
\\(x \leq \frac{?}{}\\)

Explanation:

Step1: Subtract $\frac{1}{2}x$ from both sides

$3 \geq 5x - \frac{1}{2}x + 2$

Step2: Simplify the x terms

$3 \geq \frac{10}{2}x - \frac{1}{2}x + 2$
$3 \geq \frac{9}{2}x + 2$

Step3: Subtract 2 from both sides

$3 - 2 \geq \frac{9}{2}x$
$1 \geq \frac{9}{2}x$

Step4: Multiply both sides by $\frac{2}{9}$

$\frac{2}{9} \geq x$

Answer:

$\frac{2}{9}$