Question

8.6 solve radical equations (homework) score: 6/16 answered: 6/16 question 7 find all real solutions: $sqrt{3b + 7}-10 = 0$ $b=$. (if no solution exists, enter dne)

Explanation:

Step1: Isolate the square - root term

Add 10 to both sides of the equation $\sqrt{3b + 7}-10 = 0$.
$\sqrt{3b + 7}=10$

Step2: Square both sides

Squaring both sides to eliminate the square - root. $(\sqrt{3b + 7})^2=10^2$.
$3b + 7 = 100$

Step3: Solve for b

Subtract 7 from both sides: $3b=100 - 7=93$. Then divide both sides by 3. $b=\frac{93}{3}=31$

Answer:

$31$