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QUESTION IMAGE

solve for x. round to the nearest tenth of a degree, if necessary.

Question

solve for x. round to the nearest tenth of a degree, if necessary.

Explanation:

Step1: Identify trigonometric ratio

Since we have a right - triangle with opposite side to angle $x$ of length 9 and hypotenuse of length 18, we use the sine ratio $\sin(x)=\frac{\text{opposite}}{\text{hypotenuse}}$.
So, $\sin(x)=\frac{9}{18}=\frac{1}{2}$.

Step2: Find the angle

We know that if $\sin(x)=\frac{1}{2}$, then $x = \sin^{- 1}(\frac{1}{2})$.
Using the inverse - sine function, $x = 30^{\circ}$.

Answer:

$30^{\circ}$