Question

solve for ( x ). round to the nearest tenth of a degree, if necessary.

right triangle with right angle at n, on = 1.8, nm = 1, angle at m is ( x^circ )

answer
attempt 1 out of 2
( x = ) blank ( ^circ ) submit answer

Explanation:

Step1: Identify trigonometric ratio

For angle $x^\circ$, the opposite side is $ON = 1.8$, adjacent side is $MN = 1$. Use tangent: $\tan(x) = \frac{\text{opposite}}{\text{adjacent}}$
$\tan(x) = \frac{1.8}{1}$

Step2: Solve for $x$ using arctangent

$x = \arctan(1.8)$

Step3: Calculate and round to nearest tenth

$x \approx 60.9^\circ$

Answer:

$60.9$