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solve for $x$. round to the nearest tenth, if necessary. answer attempt…

Question

solve for $x$. round to the nearest tenth, if necessary.
answer attempt 2 out of 2

Explanation:

Step1: Identify trigonometric ratio

We use sine: $\sin(\theta)=\frac{\text{opposite}}{\text{hypotenuse}}$. Here, $\theta=68^\circ$, opposite side $=96$, hypotenuse $=x$.

Step2: Substitute values into ratio

$\sin(68^\circ)=\frac{96}{x}$

Step3: Rearrange to solve for $x$

$x=\frac{96}{\sin(68^\circ)}$

Step4: Calculate the value

First, $\sin(68^\circ)\approx0.9272$, so $x\approx\frac{96}{0.9272}\approx103.5$

Answer:

$103.5$