Question

solve for $y$.
$3y^3 + 9y^2 - 54y = 0$
show your work here

Explanation:

Step1: Factor out common term

$3y(y^2 + 3y - 18) = 0$

Step2: Factor quadratic expression

$3y(y + 6)(y - 3) = 0$

Step3: Set each factor to 0

$3y=0$, $y+6=0$, $y-3=0$

Step4: Solve for y

$y=0$, $y=-6$, $y=3$

Answer:

$y=0$, $y=-6$, $y=3$