Question

solve by substitution
$2x - 7y = 13$
$3x + y = 8$
$\bigcirc$ $(-1,5)$
$\bigcirc$ $(3,2)$
$\bigcirc$ $(-2,5)$
$\bigcirc$ $(4,5)$
$\bigcirc$ $(-4,-1)$
$\bigcirc$ $(3,-1)$
$\bigcirc$ $(4,1)$
$\bigcirc$ $(1,-3)$
$\bigcirc$ $(-5,4)$
$\bigcirc$ $(0,-2)$
$\bigcirc$ no solution

Explanation:

Step1: Isolate y from second equation

$y = 8 - 3x$

Step2: Substitute y into first equation

$2x - 7(8 - 3x) = 13$

Step3: Expand and simplify equation

$2x - 56 + 21x = 13$
$23x - 56 = 13$

Step4: Solve for x

$23x = 13 + 56$
$23x = 69$
$x = \frac{69}{23} = 3$

Step5: Substitute x=3 into y=8-3x

$y = 8 - 3(3) = 8 - 9 = -1$

Answer:

(3,-1)