Question

solve the system of equations.
$-12x - 5y = 40$
$12x - 11y = 88$
$x = square$
$y = square$

Explanation:

Step1: Add the two equations

$$(-12x - 5y) + (12x - 11y) = 40 + 88$$
$$-16y = 128$$

Step2: Solve for $y$

$$y = \frac{128}{-16} = -8$$

Step3: Substitute $y=-8$ into second equation

$$12x - 11(-8) = 88$$
$$12x + 88 = 88$$

Step4: Solve for $x$

$$12x = 88 - 88 = 0$$
$$x = \frac{0}{12} = 0$$

Answer:

$x = 0$
$y = -8$