QUESTION IMAGE
Question
solve the system of linear equations using the substitution method.
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$$\begin{cases} y = 5x - 1 \\\\ y = 4x + 3 \\end{cases}$$
enter your answer as an ordered pair.
thats not it try again.
Step1: Substitute \( y \) from first equation into second
Since \( y = 5x - 1 \) and \( y = 4x + 3 \), set \( 5x - 1 = 4x + 3 \).
Step2: Solve for \( x \)
Subtract \( 4x \) from both sides: \( 5x - 4x - 1 = 4x - 4x + 3 \), so \( x - 1 = 3 \). Add 1 to both sides: \( x = 3 + 1 = 4 \).
Step3: Find \( y \) using \( x = 4 \)
Substitute \( x = 4 \) into \( y = 5x - 1 \): \( y = 5(4) - 1 = 20 - 1 = 19 \).
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\((4, 19)\)