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Question
solve the system using substitution.
3x + 6y = 27
-6x + y = -2
the solution to the system of equations in the form (x,y) is:
y = 4
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Step1: Isolate y in the second - equation
From $-6x + y=-2$, we get $y = 6x - 2$.
Step2: Substitute y into the first equation
Substitute $y = 6x - 2$ into $3x+6y = 27$. So $3x+6(6x - 2)=27$.
Expand the left - hand side: $3x+36x-12 = 27$.
Combine like terms: $39x-12 = 27$.
Add 12 to both sides: $39x=27 + 12=39$.
Divide both sides by 39: $x = 1$.
Step3: Find the value of y
Substitute $x = 1$ into $y = 6x - 2$. Then $y=6\times1 - 2=4$.
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$(1,4)$