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solving equations ii 1. solve each equation. be sure to show all necess…

Question

solving equations ii

  1. solve each equation. be sure to show all necessary steps.

$39 - 12w = 7 - 16w$
$63 - x = 2x + 3$
$12r - 18 = 13r + 18$
$-15v - 40 = 23 - 8v$

  1. solve each equation. then perform a ls/rs check.

$-x - 1 = x - 21$
$3n + 46 = 1 + 8n$

Explanation:

Response
1. Solve \( 39 - 12w = 7 - 16w \)

Step1: Add \( 16w \) to both sides

To get the variable terms on one side, we add \( 16w \) to both sides of the equation. This gives us \( 39 - 12w + 16w = 7 - 16w + 16w \), which simplifies to \( 39 + 4w = 7 \).

Step2: Subtract 39 from both sides

Now, we want to isolate the term with the variable. Subtract 39 from both sides: \( 39 + 4w - 39 = 7 - 39 \), which simplifies to \( 4w = -32 \).

Step3: Divide by 4

To solve for \( w \), divide both sides by 4: \( \frac{4w}{4} = \frac{-32}{4} \), so \( w = -8 \).

Step1: Add \( x \) to both sides

Add \( x \) to both sides to get the \( x \) terms on one side: \( 63 - x + x = 2x + 3 + x \), which simplifies to \( 63 = 3x + 3 \).

Step2: Subtract 3 from both sides

Subtract 3 from both sides: \( 63 - 3 = 3x + 3 - 3 \), so \( 60 = 3x \).

Step3: Divide by 3

Divide both sides by 3: \( \frac{60}{3} = \frac{3x}{3} \), so \( x = 20 \).

Step1: Subtract \( 12r \) from both sides

Subtract \( 12r \) from both sides: \( 12r - 18 - 12r = 13r + 18 - 12r \), which simplifies to \( -18 = r + 18 \).

Step2: Subtract 18 from both sides

Subtract 18 from both sides: \( -18 - 18 = r + 18 - 18 \), so \( r = -36 \).

Answer:

\( w = -8 \)

2. Solve \( 63 - x = 2x + 3 \)