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Question
solving simultaneous equations using substitution quick check
use the substitution method to solve the system $2.5x + y = -2$, $3x + 2y = 0$. (1 point)
○ $(3,-2)$
○ no solution
○ $(-2,3)$
○ infinite solutions
Step1: Isolate $y$ from first equation
$y = -2 - 2.5x$
Step2: Substitute $y$ into second equation
$3x + 2(-2 - 2.5x) = 0$
Step3: Simplify and solve for $x$
$3x - 4 - 5x = 0$
$-2x = 4$
$x = -2$
Step4: Substitute $x=-2$ to find $y$
$y = -2 - 2.5(-2) = -2 + 5 = 3$
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$(-2, 3)$