Question

(\frac{11}{5} \times 1 = \frac{11}{5} \times \frac{square}{square} = \frac{22}{10})

Explanation:

Step1: Analyze the equation structure

We know that \(\frac{11}{5}\times1=\frac{11}{5}\times\frac{\square}{\square}=\frac{22}{10}\). Let's denote the fraction as \(\frac{a}{b}\), so \(\frac{11}{5}\times\frac{a}{b}=\frac{22}{10}\).

Step2: Solve for the fraction

First, simplify \(\frac{22}{10}\) to \(\frac{11}{5}\) (dividing numerator and denominator by 2). Wait, no, let's do it step by step. We have \(\frac{11\times a}{5\times b}=\frac{22}{10}\). Cross - multiply: \(11\times a\times10 = 22\times5\times b\). Simplify: \(110a=110b\), so \(a = b\). But also, we know that \(\frac{11}{5}\times\frac{a}{b}=\frac{22}{10}\). Let's rewrite \(\frac{22}{10}\) as \(\frac{11\times2}{5\times2}\). So when we multiply \(\frac{11}{5}\) by \(\frac{2}{2}\) (since \(\frac{2}{2} = 1\)), we get \(\frac{11\times2}{5\times2}=\frac{22}{10}\). So the numerator and denominator of the fraction are both 2.

Answer:

The numerator is 2 and the denominator is 2, so the fraction is \(\frac{2}{2}\) (the box for numerator is 2 and the box for denominator is 2).