Question

in the square below, $m\angle fep = (10x + 10) ^\circ$. find $x$.

Explanation:

Step1: Identify angle property of square

The diagonals of a square intersect at a right angle, so $m\angle FEP = 90^\circ$.

Step2: Set up equation

$$10x + 10 = 90$$

Step3: Isolate the term with $x$

Subtract 10 from both sides:
$$10x = 90 - 10$$
$$10x = 80$$

Step4: Solve for $x$

Divide both sides by 10:
$$x = \frac{80}{10}$$

Answer:

$x = 8$