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a student measures the mass of a 1.00 g piece of aluminum and finds it …

Question

a student measures the mass of a 1.00 g piece of aluminum and finds it to be 0.99 g. what is the percent error of the students measurement?
0.1%
1%
0.01%
10%

Explanation:

Step1: Calculate the error

Error = True value - Measured value. Here, the true value is $1.00$ g and the measured value is $0.99$ g. So, Error = $1.00 - 0.99=0.01$ g.

Step2: Calculate the percent - error

The formula for percent - error is $\text{Percent Error}=\frac{\text{Error}}{\text{True Value}}\times100\%$. Substitute the values: $\text{Percent Error}=\frac{0.01}{1.00}\times 100\% = 1\%$.

Answer:

B. 1%