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subtract 3h from both sides of the equation to get rid of the 3h on the…

Question

subtract 3h from both sides of the equation to get rid of the 3h on the left, so that all the h terms are on the right side of the equation.\\
\\(\frac{1}{5}(15h - 10)\\) = \\(8h + 8\\)\\
\\(3h - 2\\) = \\(8h + 8\\)\\
\\(-3h\\) \\(-3h\\)\\
\\(\square\\) = \\(\square\\)

Explanation:

Step1: Simplify left side first

First, expand the left side:
$$\frac{1}{5}(15h - 10) = 3h - 2$$

Step2: Subtract 3h from left side

$$3h - 2 - 3h = -2$$

Step3: Subtract 3h from right side

$$8h + 8 - 3h = 5h + 8$$

Answer:

Left box: $\boldsymbol{-2}$
Right box: $\boldsymbol{5h + 8}$