Question

sullys day
sullys blood pressure starts at 90 and rises 5 points every hour for the first 4 hours. sully chills out for lunch from 12 - 1 and maintains a cool 110 blood pressure. last period of the day hits from 1 - 3 and sullys blood pressure rises from 110 at 10 points per hour. school ends and sullys blood pressure starts dropping 2 points per hour until his 8 oclock bedtime.

1. graphically sullys blood pressure changes throughout the school day. sketch a graph of his blood pressure over time. label the graph! let x stand for the time since 0800, so 1000 would be x = 2, 1200 would be x = 4, etc...

Explanation:

Step1: Analyze initial - state

At 0800 ($x = 0$), blood - pressure starts at 90.

Step2: Calculate blood - pressure from 0800 to 1200

From 0800 to 1200 ($x$ from 0 to 4), it rises 5 points per hour. So the blood - pressure $y$ at $x$ hours in this period is $y=90 + 5x$. At $x = 4$ (1200), $y=90+5\times4=110$.

Step3: Analyze lunch - time

From 1200 - 1300 (lunch, $x$ from 4 to 5), blood - pressure is 110.

Step4: Analyze 1300 - 1500

From 1300 - 1500 ($x$ from 5 to 7), it rises 10 points per hour. The formula for this period is $y = 110+10(x - 5)$. At $x = 7$ (1500), $y=110+10\times(7 - 5)=130$.

Step5: Analyze after - school

After school (after $x = 7$), it drops 2 points per hour until bedtime at $x = 12$ (2000). The formula is $y=130-2(x - 7)$.

To sketch the graph:

• Mark the time ($x$) on the horizontal axis (ranging from 0 to 12) and blood - pressure ($y$) on the vertical axis (ranging from 90 to 140).
• Plot the points: $(0,90)$, $(4,110)$, $(5,110)$, $(7,130)$.
• Connect the points with line - segments according to the described changes.

Answer:

Sketch a graph with time ($x$) on the horizontal axis (0 - 12 representing 0800 - 2000) and blood - pressure ($y$) on the vertical axis (90 - 140). Plot points $(0,90)$, $(4,110)$, $(5,110)$, $(7,130)$ and connect them with line - segments based on the rate of change in each time - interval.