Question

suppose that the function f is defined on the interval (-2, 2 as follows.
$f(x)=\

$$\begin{cases} -1 & \\text{if } -2 < x \\leq -1 \\\\ 0 & \\text{if } -1 < x \\leq 0 \\\\ 1 & \\text{if } 0 < x \\leq 1 \\\\ 2 & \\text{if } 1 < x \\leq 2 \\end{cases}$$

$
find $f(-1)$, $f(1.25)$, and $f(2)$.
$f(-1) = \square$
$f(1.25) = \square$
$f(2) = \square$

Explanation:

Step1: Match $x=-1$ to interval

$-1$ satisfies $-2 < x \leq -1$, so $f(-1)=-1$

Step2: Match $x=1.25$ to interval

$1.25$ satisfies $1 < x \leq 2$, so $f(1.25)=2$

Step3: Match $x=2$ to interval

$2$ satisfies $1 < x \leq 2$, so $f(2)=2$

Answer:

$f(-1) = -1$
$f(1.25) = 2$
$f(2) = 2$