Question

suppose that the point (x, y) is in the indicated quadrant. decide whether the given ratio is positive or negative. recall that $r = sqrt{x^{2}+y^{2}}$.
in quadrant ii, is $\frac{r}{x}$ positive or negative?
positive
negative

Explanation:

Step1: Recall properties of quadrant II

In quadrant II, $x<0$ and $r = \sqrt{x^{2}+y^{2}}>0$.

Step2: Analyze the sign of the ratio

Since $r>0$ and $x < 0$, then $\frac{r}{x}<0$.

Answer:

Negative