Question

swimming pool: calculate the pressure 2 meters below the surface in a swimming pool. (water density = 1000 kg/m³)
p = pa

Explanation:

Step1: Recall pressure - depth formula

$P = P_0+
ho gh$, where $P_0$ is atmospheric pressure, $
ho$ is fluid density, $g$ is acceleration due to gravity ($g = 9.8\ m/s^{2}$), and $h$ is depth. Assuming we want gauge - pressure (pressure above atmospheric pressure), $P_0 = 0$.

Step2: Substitute values

$
ho=1000\ kg/m^{3}$, $g = 9.8\ m/s^{2}$, $h = 2\ m$. Then $P=
ho gh=1000\times9.8\times2$.

Step3: Calculate result

$P = 19600\ Pa$.

Answer:

$19600$