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talib is trying to find the inverse of the function to the right. his w…

Question

talib is trying to find the inverse of the function to the right. his work appears beneath it. is his work correct? explain your answer.
$f(x) = -8x + 4$
$y = -8x + 4$
$y - 4 = -8x$
$x = (y - 4)/-8$
$f^{-1}(x) = (y - 4)/-8$

Explanation:

Step1: Recall inverse function steps

To find the inverse of a function \( y = f(x) \), we swap \( x \) and \( y \) and then solve for \( y \). The general steps are: 1. Replace \( f(x) \) with \( y \). 2. Swap \( x \) and \( y \). 3. Solve for \( y \). 4. Replace \( y \) with \( f^{-1}(x) \).

Step2: Analyze Talib's work

  • Talib started with \( y=-8x + 4 \), then got \( y - 4=-8x \), then \( x=\frac{y - 4}{-8} \). But when finding the inverse, after solving for \( x \) in terms of \( y \), we need to swap \( x \) and \( y \) (i.e., replace \( x \) with \( y \) and \( y \) with \( x \)) in the final expression for the inverse function.
  • Talib's final step has \( f^{-1}(x)=\frac{y - 4}{-8} \), but \( y \) should be replaced with \( x \) here. The correct step after \( x=\frac{y - 4}{-8} \) is to rewrite it as \( y=\frac{x - 4}{-8} \) (by swapping \( x \) and \( y \)) and then \( f^{-1}(x)=\frac{x - 4}{-8}=\frac{-x + 4}{8} \) (simplifying the fraction).
Brief Explanations

To find the inverse of a function \( y = f(x) \), we follow these steps:

  1. Replace \( f(x) \) with \( y \) (Talib did this: \( y=-8x + 4 \)).
  2. Swap \( x \) and \( y \) (Talib skipped this crucial step when defining \( f^{-1}(x) \)).
  3. Solve for \( y \): From \( y=-8x + 4 \), we get \( y - 4=-8x \), then \( x=\frac{y - 4}{-8} \). After swapping \( x \) and \( y \), we should have \( y=\frac{x - 4}{-8} \), so \( f^{-1}(x)=\frac{x - 4}{-8} \) (or simplified, \( f^{-1}(x)=\frac{-x + 4}{8} \)).

Talib’s error is in the final step: he left \( y \) in the expression for \( f^{-1}(x) \) instead of replacing \( y \) with \( x \) (after swapping \( x \) and \( y \)).

Answer:

Talib's work is incorrect. When finding the inverse function, after solving for \( x \) in terms of \( y \) (\( x=\frac{y - 4}{-8} \)), we must swap \( x \) and \( y \) (replace \( x \) with \( y \) and \( y \) with \( x \)) to get the inverse function. Talib failed to replace \( y \) with \( x \) in the final expression for \( f^{-1}(x) \); the correct inverse should be \( f^{-1}(x)=\frac{x - 4}{-8} \) (or simplified as \( f^{-1}(x)=\frac{-x + 4}{8} \)).