Question

temperature conversions practice
name
date
period
celsius to kelvin: ( k = ^circ c + 273 ); ( k = ^circ c + 273 )
kelvin to celsius: ( ^circ c = k - 273 ); ( ^circ c = k - 273 )
fahrenheit to celsius: ( ^circ c = (^circ f - 32) \times \frac{5}{9} ); ( ^circ c = (^circ f - 32) \times \frac{5}{9} )
convert the following temperatures to | k | c | show your work here |
0.5 k
100 k
207 k
521 k
-273 ( ^circ c )
-150 ( ^circ c )
-10 ( ^circ c )
0 ( ^circ c )
0.5 ( ^circ c )
100 ( ^circ c )
207 ( ^circ c )
521 ( ^circ c )
-40 ( ^circ f )
0 ( ^circ f )
32 ( ^circ f )
75 ( ^circ f )
100 ( ^circ f )
212 ( ^circ f )

Explanation:

Let's take one of the temperature conversion problems, for example, converting \(-273^\circ \text{C}\) to Kelvin. We'll use the formula \(K = ^\circ\text{C}+ 273\).

Step 1: Identify the formula and given value

We know the formula to convert Celsius to Kelvin is \(K = ^\circ\text{C}+ 273\), and the given Celsius temperature is \(-273^\circ \text{C}\).

Step 2: Substitute the value into the formula

Substitute \(^\circ\text{C}=- 273\) into the formula \(K = ^\circ\text{C}+ 273\), we get \(K=-273 + 273\).

Step 3: Calculate the result

\(-273+273 = 0\), so \(K = 0\space K\)

Another example, converting \(0^\circ\text{C}\) to Kelvin:

Step 1: Identify the formula and given value

The formula is \(K = ^\circ\text{C}+ 273\), and \(^\circ\text{C} = 0\)

Step 2: Substitute the value into the formula

\(K=0 + 273\)

Step 3: Calculate the result

\(K = 273\space K\)

For converting \(100^\circ\text{C}\) to Kelvin:

Step 1: Identify the formula and given value

Formula \(K = ^\circ\text{C}+ 273\), \(^\circ\text{C}=100\)

Step 2: Substitute the value into the formula

\(K = 100+273\)

Step 3: Calculate the result

\(K=373\space K\)

For converting \(0.5\space K\) to Celsius:

Answer:

Step 1: Identify the formula and given value

The formula to convert Fahrenheit to Celsius is \(^\circ\text{C}=\frac{5}{9}(^\circ\text{F}- 32)\), and \(^\circ\text{F}=-40\)

Step 2: Substitute the value into the formula

\(^\circ\text{C}=\frac{5}{9}(-40 - 32)\)

Step 3: Calculate the value inside the parentheses

\(-40-32=-72\)

Step 4: Multiply by \(\frac{5}{9}\)

\(^\circ\text{C}=\frac{5}{9}\times(-72)=- 40^\circ\text{C}\)

If you want to solve other temperature conversion problems in the table, you can follow the similar steps using the corresponding temperature conversion formulas (\(K = ^\circ\text{C}+ 273\), \(^\circ\text{C}=K - 273\), \(^\circ\text{C}=\frac{5}{9}(^\circ\text{F}-32)\)) and substitute the given temperature values into the formulas to calculate the required temperature units.